A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
Its slope would be:
[tex]m = \dfrac{y-q}{x-p}[/tex]
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
[tex]m = \dfrac{y-q}{x-p}\\\\ m = \dfrac{-5-6}{2+4}\\\\ m = \dfrac{-11}{6}[/tex]
The equation of a line is
[tex]( y -y_0) = m (x - x_0)\\\\( y -6) = \dfrac{-11}{6} (x+4)\\\\6( y -6) = (-11) (x+4)\\\\6y -36 = (-11x +44)\\\\11x +6y - 80 = 0[/tex]
Hence, the equation is 11x +6y - 80 = 0
Learn more about slopes here:
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