The volume which is occupied by 0.445 mol of carbon dioxide at 397K and 973mmHg is 11.32 L.
Ideal gas equation will be represented as:
PV = nRT, where
P = pressure = 973 mmHg = 1.28 atm
V = volume = ?
n = moles = 0.445 mol
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 397 K
On putting all these values, we get moles as:
V = (0.445)(0.082)(397) / (1.28) = 11.317 = 11.32 L
Hence required volume of gas is 11.32 L.
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