The integration of the function f(x, y) = 2x²y³ from 0 to 3 with respect to x is 27y³.
It is the reverse of differentiation.
The function f(x, y) is given below.
f(x, y) = 2x²y³
Then the integration of the function from 0 to 3 with respect to x.
[tex]\begin{aligned} \rm \int_{0}^{3}f(x, y)dx &= \rm \int_{0}^{3}9x^2y^3 dx \\\\&= \rm 9y^3 \ \int_{0}^{3} x^2 dx\\\\&= \rm 9y^3 (\dfrac{x^3}{3}) _{0}^{3}\\\\&= \rm3y^3 (3^3 - 0 ^3)\\\\&= \rm 3y^3 \times 9\\\\&= \rm 27y^3 \end{aligned}[/tex]
More about the integration link is given below.
https://brainly.com/question/18651211
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