If the value of a and e is 5 and 4, then the value of b is 3. Then the equation of the ellipse will be given below.
[tex]\rm \dfrac{x^2 }{25} +\dfrac{y^2}{9} = 1[/tex]
Ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called foci adds up to a constant. It is taken from the cone by cutting it at an angle.
The vertices (±5,0) and foci (±4,0) are given. Then the equation of the ellipse will be
We know that the general equation of the ellipse will be
[tex]\rm \dfrac{x^2 }{a^2} +\dfrac{y^2}{b^2} = 1[/tex]
Then the value of a will be
a = 5
And the value of the eccentricity will be
e = 4/5
Then the value of the b will be
[tex]\rm b^2 = a^2 - a^2e^2\\\\b^2 = 5^2 - 5^2 \times \dfrac{4^2}{5^2}\\\\b^2 = 25 - 16\\\\b \ = 3\\[/tex]
Then the equation will be
[tex]\rm \dfrac{x^2 }{5^2} +\dfrac{y^2}{3^2} = 1\\\\\rm \dfrac{x^2 }{25} +\dfrac{y^2}{9} = 1[/tex]
More about the ellipse link is given below.
https://brainly.com/question/19507943
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