If the plane of the loop is perpendicular to the magnetic field then the θ will be zero. Then the torque will also be zero.
The torque that may cause an item to revolve along an axis is measured as torque. The axis of rotation is the point at which the item rotates.
A rectangular coil of wire, 22.0cm by 35.0cm and carrying a current of 1.95 Ampere, is oriented with the plane of its loop perpendicular to a uniform 1.50 Tesla magnetic field.
Then the torque that the magnetic field exerts on the coil will be
The torque is given as
[tex]\rm \tau = I \overrightarrow{A} \times \overrightarrow{B}[/tex]
The strength of magnetic torque on the current-carrying circle is given by θ: if θ is the angle between A and B. Then we have
[tex]\rm \tau = I AB \sin \theta[/tex]
When the loop plane is perpendicular to the magnetic field, the amplitude of magnetic torque on the current-carrying circle is zero.
Then θ = 0
Then we have
[tex]\rm \tau = I AB \sin 0\\\\\tau = 0[/tex]
More about the torque link is given below.
https://brainly.com/question/6855614
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