Respuesta :

Answer:

Has infinite solutions

Explanation:

-x + 5y = -3..... eq1

2x - 10y = 6 .... eq2

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make x the subject in equation 1

-x + 5y = -3

-x = -3 - 5y

x = 5y + 3

========= insert this in equation 2

2(5y + 3) - 10y = 6

10y + 6 -10y = 6

6 = 6

So, Has infinite solutions as L.H.S = R.H.S