The corresponding z score for a grade of 81.8% for a class with average grade of 83% and standard deviation of 4.2% is -0.29.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Given that mean is 83%, standard deviation = 4.2%, for x = 81.8:
z = (81.8 - 83)/4.2 = -0.29
The corresponding z score for a grade of 81.8% for a class with average grade of 83% and standard deviation of 4.2% is -0.29.
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