Respuesta :
z^25 needs to be z^24 to make a perfect cube
if z^24 then
125x^18y^3z^24 = 5^3 (x^6)^3 y^3 (z^8)^3
Answer:
[tex]z^{25}[/tex] has to be changed.
Step-by-step explanation:
The given monomial is [tex]125x^{18}y^{3}z^{25}[/tex].
If we see the separate terms of the monomial then we find that each term can be written in perfect cube form except z.
125 = 5³
[tex]x^{18}=(x^{6})^{3}[/tex]
y³ is in cube form
[tex]z^{25}[/tex] is the only term which can be written in the perfect cube form if it is [tex]z^{24}=(z^{8})^{3}[/tex] or [tex]z^{27}=(z^{9})^{3}[/tex]
So the answer is [tex]z^{25}[/tex]
