statement best describes the difference of the mean of the two data sets 2.8 is about 1.5 times the mean absolute deviation of either set.
What is mean?
Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers.
The mean of William's set.
To find the mean, add all of the data points together and divide by the number of data points:
=89+90+97+74+78/5
=85.6
Now, mean absolute deviation,
=|89-85.6|+|90-85.6|+|97-85.6|+|74-85.6|+|78-85.6|/5
= 3.4+4.4+11.4+11.6+7.6/5
=7.68.
The mean of Andre's set.
To find the mean, add all of the data points together and divide by the number of data points:
=73+81+87+91+82/5
=82.8
Now, mean absolute deviation,
=|73-82.8|+|81-82.8|+|87-82.8|+|91-82.8|+|82-82.8|/5
=9.8+1.8+4.2+8.2+0.8/5
= 4.96.
Hence, the difference between the means of the two sets is
85.6-82.8=2.8.
2.8 is about 1.5 times the mean absolute deviation of either set.
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