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[tex]\sf\large\green{\underbrace{\red{Question*}}}:[/tex]
[tex] \mathbb\blue{SOLVE} [/tex]
[tex] \pink{1. \: \: \: \: \: \: (3 - x)(x + 2) = 0}[/tex]
[tex] \pink{2. \: \: \: \: \: {(q + 2)}^{2} - 40}[/tex]
​

Respuesta :

[tex]\large{\underline{\underline{\pmb{\sf{\color {red}{Solve:}}}}}}[/tex]

[tex] \sf \red{1. \: (3x - x) (x + 2) = 0}[/tex]

[tex] \sf \red{2. \: (q + 2)^{2} - 40}[/tex]

[tex]\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}[/tex]

2.soln:

(q + 2)² - 40

=> (q)² + 2.q.2 + (2)² - 40

=> q² + 4q + 4 - 40

=>q² + 4q - 36

Here, a = 1, b = 4 and c = - 36

By, using Quadratic formula

See the attachment

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