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The age of a father is 2 less than 7 times the age of his son. In 3 years, the sum of their ages will be 52. If the son’s present age is s years, which equation models this situation? A. B. C. D.

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Answer:

First,

the age of the son: s

the age of the father is 2 less than 7 times the age of his son: 7s - 2

In 3 years, the sum of their ages will be 52, In 3 years, the age of the sun will

increase 3, so s+3. Also, the age of his

father also increase 3, (7s-2)+3

(s+3)+ [(7s-2)+3] = 52 is the equation.

The correct answer is :

( 7s - 2 ) +3+ ( s + 3 ) = 52 , or 8s + 4 = 52 .

Explanation :

Since s is the son's age , " two less than seven times " the son's age would be represented by 7s - 2 .

To represent this in 3 years , we would add 3 : ( 7s - 2 ) +3 .

In 3 years , the son's age , s , would be represented by s + 3 . We are told that the sum of these ages will be 52 ; this gives us ( 7s - 2 ) +3+ ( s + 3 ) = 52 .

To simplify this , combine like terms .

7s + s = 8s ; -2 + 3 + 3 = 4 .

This gives us 8s + 4 = 52 .

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