[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's solve for x ~
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + 5x + 6 = 0[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + 3x + 2x + 6 = 0[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}^{}( x+ 3) + 2(x + 3)= 0[/tex]
[tex]\qquad \sf \dashrightarrow \: {}^{}( x+ 2)(x + 3)= 0[/tex]
[tex] \begin{cases} \sf \: x = - 2 \: \: \: \: \: \: \: \sf if \: (x + 2) = 0 \\ \\ \sf \: x = - 3 \: \: \: \: \: \: \: if \: (x + 3) = 0\end{cases} [/tex]
I hope that helps ~
