Answer:
b=204
Step-by-step explanation:
The law of sine states that: [tex]\frac{SinA}{a} =\frac{SinB}{b} =\frac{SinC}{c}[/tex]
We know that a triangle has 180° total, so we can subtract the two angle measures we know to find the third angle: [tex]180-90-41=49[/tex]°.
Using these two things, we can come up with the equality [tex]\frac{Sin90^{o} }{270} =\frac{Sin49^o}{b}[/tex], which we can use to solve for side b.
[tex]\frac{Sin90^o}{270} =\frac{1}{270}[/tex], so we know that [tex]\frac{1}{270} =\frac{Sin49^o}{b}[/tex].
Next, we would multiply both sides by b to get [tex]\frac{1}{270}b=Sin49^o[/tex].
Sin49°≈0.75471, so to find b we would multiply 0.75471×270=203.77
Since the problem asks us to round to the nearest whole number, b=204
Hope this helps! :)
