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What volume of a 0.252 M hydroiodic acid solution is required to neutralize 18.0 mL of a 0.151 M barium hydroxide solution

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Medunno13

Answer: 10.8 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(0.252)V_{A}=(18.0)(0.151)\\V_{A}=\frac{(18.0)(0.151)}{(0.252)} \approx \boxed{10.8 \text{ M}}[/tex]

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