The surface area of the capsule is 2.36in^2.
We have given that,
diameter=0.5 inches
radius=dimeter/2=0.5/2=0.25
[tex]\pi =3.14[/tex]
Surface area=2(curved surface area of the hemisphere)+curved surface area of the cylinder.
[tex]=2(2\pi r^{2})+2\pi rh\\ =4\pi r^{2}+2\pi rh\\=4(3.14)(0.25)^2+2(3.14)(0.25)(1)\\=0.785+1.57\\=2.36[/tex]
Therefore the surface area of the capsule is 2.36in^2.
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