Use technology or a z-score table to answer the question.
The weights of boxes of rice produced at a factory are normally distributed with a
mean of 20 ounces and a standard deviation of 1.5 ounces. Consider a shipment of 1500 boxes of rice.
How many of the boxes will weigh 18 ounces or less?
138 boxes
154 boxes
632 boxes
781 boxes

Respuesta :

The number of boxes will weigh 18 ounces or less will be 138. Then the correct option is A.

What is a normal distribution?

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z-score is given as

z = (x - μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

The weights of boxes of rice produced at a factory are normally distributed with a mean of 20 ounces and a standard deviation of 1.5 ounces.

Consider a shipment of 1500 boxes of rice.

Then the number of the boxes will weigh 18 ounces or less will be

z = (18 - 20) / 1.5

z = -1.33

Then the probability will be

P(x ≤ 18) = P(z ≤ -1.33)

P(x ≤ 18) = 1 - P(z > -1.33)

P(x ≤ 18) = 1 - [1 - P(z < -1.33)]

P(x ≤ 18) = P(z < -1.33)

P(x ≤ 18) = 0.091211

Then the number of the boxes will weigh 18 ounces or less will be

⇒ 0.091211 x 1500

⇒ 136.8

approximately 138 boxes.

Then the correct option is A.

More about the normal distribution link is given below.

https://brainly.com/question/12421652

#SPJ1