The balloon must be heated to a temperature of 150 °C in order to have a volume of 6.00 L.
The volume of a gas is directly proportional to the temperature of the gas.
According to Charles' law: V1/T1 / = V2/T2
V1 =4.0 L
T1 = 9°C = (273. + 9) K = 282 K
V2 = 6.0 L
T2 = ?
T2 = V2×T1/V1
T2 = 6 × 282 / 4 = 423 K
423.2 K = 423 -273 = 150 °C
Therefore, the balloon must be heated to a temperature of 150 °C in order to have a volume of 6.00 L.
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