The velocity 2.5 m above the ground will be 49.07 m/sec.
The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;
F = kx
The formula for force is;
F=ma
Equating both the equation;
ma = kx
a=kx/m
a=( 185 N/m × 1.38 m) / 0.53
a = 481.6 m/s²
The speed is found by Newton's third equation of motion;
v²=u²+2as
v²=0+2as
v²=2 × 481.6 m/s² × 2.5 m
v = 49.07 m/sec
Hence the velocity 2.5 m above the ground will be 49.07 m/sec.
To learn more about the spring force refer to the link;
https://brainly.com/question/4291098
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