Answer:
17.25g
Explanation:
From our question, we have been asked to find the mass of water present.
The formula for finding specific heat is given by;
Q = mCp∆T
We have, Q = 0.507 J, ∆T = 0.007° C and we know that Cp of water is 4.2 J/g°C
Rearrange the formula making m the subject.
Which is given by;
m = (Q)/(Cp∆T)
Substituting for the known values
[tex]m \: = \frac{0.507}{4.2 \times 0.007}[/tex]
= 17.24489 g
= 17.25g
Answer:
17.32 gm
Explanation:
Specific heat of water is 4.182 J / g- c
4.182 J /g-c = .507/ ( .007 * gm)
solve for gm = 17.32 gm
