Answer:
1.20 M (3 s.f.)
Explanation:
In this question, we are trying to find the concentration of KCl after dilution. Note that the number of moles of KCl does not change.
[tex]g \div \frac{g}{mol} = g \times \frac{mol}{g} = mol[/tex]
Number of moles of KCl
= 44.7 ÷74.55
= 0.59960 mol (5 s.f.)
New volume
= 500 mL
= (500 ÷1000) L
= 0.5 L
Concentration after dilution
= 0.59960 ÷0.5
= 1.1992 mol/L
= 1.20 M (3 s.f.)
* M is the symbol for Molarity, which is also equal to mol/L
