The image of ΔABC after a reflection across Line E G is ΔA'B'C'.

2 triangles are shown. Line E G is the line of reflection. Line segment D D prime has a midpoint at point F. Line segment C C prime has a midpoint at point G. Points B and B prime share a point. Angle C G F is a right angle.
Which triangle must be a right triangle and why?

ΔA'B'C' is right because it is the image of ΔABC.
ΔADC is right because AA' intersects AC at A.
ΔBCC' is right because B lies of the line of reflection.
ΔBGC is right because Line E G is perpendicular-to CC'.

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ayoushivt ayoushivt · Answer 1 · 2022-07-05T07:52:02+02:00

ΔDGC is right because Line E G is perpendicular-to CC', Option D is the correct answer.

Reflection along a line is plotting a new object as a mirror image of the original object .

It is given that the there are two Triangles , ABC and A'B'C' as an image.

The figure is attached with the answer.

D is the mid point of the line joining BB'

As the line of reflection is always perpendicular to the object and the image.

And as it is given that C G F is a right angle.

Therefore triangle DGC is right angled triangle , (the option given in the question is incorrect ) , Line E G is perpendicular-to CC'.

Option D is the correct answer.

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