Answer:
101.18 grams
Explanation:
From the equation you can see that the same number of MOLES will be required as MOLES of aluminum chloride produced.
Mole weight of aluminum chloride = 26.981 + 3 * 35.45 = 133.331 gm
500 gms of this is then 500 / 133.331 = 3.75 moles
So you need 3.75 moles of aluminum
3.75 moles * 26.981 g/mole = 101.18 grams of Al
