Respuesta :
Answer: 0.70 moles
Explanation:
[tex]2Al+3Cl_2\rightarrow 2AlCl_3[/tex]
As can be seen from the chemical equation, 2 moles of aluminium react with 3 moles of chlorine.
According to mole concept, 1 mole of every substance weighs equal to its molar mass.
Moles of Al =[tex]\frac{\text{ given mass of Al}}{\text{ molar mass of Al}}= \frac{19g}{27g/mole}=0.70moles[/tex]
As aluminium is the limiting reagent as it limits the formation of product and chlorine is the excess reagent as it is left unreacted.
2 moles of aluminium reacts to produce 2 moles of aluminium chloride.
0.70 of aluminium reacts to form =[tex]\frac{2}{2}\times 0.70=0.70moles[/tex] of aluminium chloride.
Thus 0.70 moles of aluminium chloride will be formed.
The number of moles of aluminum chloride that could be produced is 0.704 moles
First, we will write a balanced chemical equation for the reaction
The balanced chemical equation for the reaction between aluminum and chlorine is
2Al + 3Cl₂ → 2AlCl₃
This means 2 moles of aluminum (Al) will react with 3 moles of chlorine (Cl₂) to produce 2 moles of aluminum chloride (AlCl₃)
Now, to determine the number of moles of aluminum chloride that could be produced,
We will determine the number of moles of aluminum present in 19.0 g of Al
Using the formula
[tex]Number\ of \ moles = \frac{Mass}{Molar\ mass}[/tex]
Mass of aluminum = 19.0 g
Molar mass of aluminum = 26.98 g/mol
∴ Number of moles of aluminum present = [tex]\frac{19.0}{26.98}[/tex]
Number of moles of aluminum present = 0.704 moles
Since,
2 moles of aluminum (Al) reacts to produce 2 moles of aluminum chloride (AlCl₃)
Then,
0.704 moles of aluminum (Al) will react to produce 0.704 moles of aluminum chloride (AlCl₃)
Hence, the number of moles of aluminum chloride that could be produced is 0.704 moles
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