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A 83.5 g sample of a nonelectrolyte is dissolved in 291.7 g of water.
The solution is determined to have a boiling point of 102.3 °C. What is
the molar mass of the compound? (Kb for water is 0.510 °C/m).

Respuesta :

ajinems

The molar mass of the compound is = 1.42g/ mol

Calculation of compound molar mass

∆Tb = kB × molarity

∆Tb = 102.3°C

Kb = 0.510 °C/m

Molarity= electrolyte mass × water solubility/ Mw× mass of water.

That is,

102.3°C= 0.51× 83.5×1000/Mw × 291.7

Make Mw the subject of formula,

Therefore,

Mw = 0.51 × 83.5×1000/ 102.3 × 291.7

Mw= 42,585/29,840.91

Mw= 1.42g/mol

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