The rate of the slower jet is 672 miles per hour.
The rate of the slower jet is 752 miles per hour.
How to find the rate of the jets?
Two jets leave an air base at the same time and travel in opposite directions.
One jet travels 80 mi/h faster than the other.
let
x = rate of the slower jet
faster jet = 80 + x
Therefore,
rate = distance / time
The two jets are 11392 miles apart.
(80 + x)8 + 8x = 11392
640 + 8x + 8x = 11392
640 + 16x = 11392
16x = 11392 - 640
16x = 10752
divide both sides by 16
x = 10752 / 16
x = 672 miles per hour
rate of the faster jet = 80 + 672 = 752 miles per hour
learn more on rate here: https://brainly.com/question/13975895
#SPJ1
