Balance the equation in acidic conditions. phases are optional. equation: cu no_{3}^{-} -> cu^{2 } no cu no−3⟶cu2 no

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the given equation

Cu + NO₃⁻ → Cu⁺² + NO₂

Here we can see that all atoms other than O and H are balanced.

In the given equation oxidation number of Cu changes from 0 to +2.

In the given equation oxidation number of N changes from 5 to 4.

Now multiply by 2 with NO₃⁻ and NO₂.

Cu + 2NO₃⁻ → Cu⁺² + 2NO₂

Now ad the water molecules in right hand side to balanced the O atoms.

Cu + 2NO₃⁻ → Cu⁺² + 2NO₂ + 2H₂O

Now add 4H⁺ on the left hand side to balance the H atoms.

Cu + 2NO₃⁻ + 4H⁺ → Cu⁺² + 2NO₂ + 2H₂O

Thus from the above conclusion we can say that Cu + 2NO₃⁻ + 4H⁺ → Cu⁺² + 2NO₂ + 2H₂O this is the balanced chemical equation in acidic medium.

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

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