Ice at 0. 0∘c has a density of 917 kg/m3. a 3. 00 cm3 ice cube is gently released inside a small container filled with oil and is observed to be neutrally buoyant. what is the density of the oil, rhooil?

Respuesta :

The density of the oil is 917kg/ m³.

An object is said to be naturally buoyant when ithas the tendency to float in a fluid.

from the law of floating when a body float in a liquid,the weight of the liquid displaced by its immersed part is equal to the total weight of body.

That is

weight (w)=upthrust (u)

w=u

therefore

u=Dvg

where, D= density of the ice

v= volume of ice

g= acceleration due to gravity

from the question

given:

 D  = 917kg/m {}^{3} [/tex]

v = 3.00cm {}^{3} [/tex]

g = 9.8m/s {}^{2} [/tex]

substitute these values in above equation

u = 917(3 \times 10 {}^{ - 6} )(9.8)[/tex]

u=0.027N

but,

upthrust= weight of oil displaced.And the ice will displaced an amount of oil,equal to its own weight.

therefore,

density of oil = u/gv = (0.027)/3 \times 10 {}^{ - 6)} (9.8)[/tex]

density of oil = 917kg/m {}^{3} [/tex]

hence the density of the oil is 917kg/m {}^{3} [/tex]

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