[tex]e-\frac{1}{e} +\frac{4}{3} 0r 3.687[/tex] is the value when the equation is to integrate with respect to x or y
we integrate with respect to x
Area = [tex]\int\limits^b_a{(f(x)-g(x))} \, dx[/tex]
= [tex]\int\limits^1_-1{e^{x}-x^{2} +1 } \, dx[/tex]
=[tex]e^{x} -\frac{x^{3} }{3} +x[/tex]
substitute 1 and -1 in place of x
= [tex](e-\frac{1}{3}+1-\frac{1}{e} -\frac{1}{3} +1)[/tex]
= [tex]e-\frac{1}{e} + \frac{4}{3} or 3.6837[/tex]
The diagram was attached in the given below.
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