Respuesta :
[tex]NO_{2}[/tex](g) + OH(g) = [tex]HNO_{3}[/tex] (aq) (nitric acid)
Given,
Pressure of [tex]NO_{2}[/tex] = 4.5x10-8 atm,
volume = 1.3x109 L, and
temp = 10ºC + 273 = 283K
moles. NO2 =? = n
PV = nRT
n = PV/RT = (4.5x10-8 atm)(1.3x109 L) / (0.0821 Latm/Kmol) (210K)
n = 3.4x10-18 moles NO2 = mols HNO3
mass HNO3 = 3.4 x 10 18 moles x 31 g/mol = 1.05 x 10 16 g.
Nitric acid
The inorganic substance nitric acid has the formula HNO3. This mineral acid is extremely corrosive. [5] Even though the chemical is colorless, older samples often have a yellow tinge from breakdown into nitrogen oxides. Nitric acid is 68 percent concentrated in water in the majority of commercially available products. Fumigating nitric acid is the term used to describe a solution that contains more than 86 percent HNO3. Depending on the quantity of nitrogen dioxide, fuming nitric acid is further classified as red fuming nitric acid at concentrations above 86 percent or white fuming nitric acid at concentrations above 95 percent. The main chemical used in nitration, or adding a nitro group usually to an organic molecule, is nitric acid.
How many grams of nitric acid are produced from this reaction if it reduces the partial pressure of no2 from a 1. 3×109l volume of air over a city by 4. 5×10−8atm when the temperature is 10∘c?
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