The value of trigonometry terms sin(2x) is 120/169 and cos(2x) is 119/169 and tan(2x) is 120/119.
According to the statement
We have given that the sin(x) = 5/13 , x in quadrant iii
And we have to Find the value of cos x using the following:
So, For this purpose, we know that the trigonometry terms are:
sin2(x) + cos2(x) = 1;
or cos2(x) = 1-sin2(x)
And
cos2(x) = 1-(-5/13)2 =
cos2(x) = 144/169;
We know that the
In quadrant III both the sin and cos are negative so
cos(x) = -12/13 (after taking square roots).
And
Then tan(x) = sin(x)/cos(x) = (-5/13)/(-12/13) = 5/12.
Now you can use the angle addition formulas to find sin(2x), cos(2x), and tan(2x).
Now
sin(x + x) = sinx * cosx + cosx * sinx
= (-5/13)*(-12/13) + (-12/13)(-5/13) = 120/169
And
cos(x + x) = cosX * cos(x) - sinx*sinx
= (-12/13)(-12/13) - (-5/13)(-5/13)
= 119/169
So,
You could use the tan double angle formula, but it is easiest to use
tan(2x) = sin(2x)/cos(2x) = (120/169) / (119/169)
= 120/119.
So, The value of trigonometry terms sin(2x) is 120/169 and cos(2x) is 119/169 and tan(2x) is 120/119.
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