The stock solution should have a molarity of 8.24M.
Proportional sets. C₁V₁=C₂V₂ is used to calculate an unknown quantity where two solutions/mixtures are proportional.
It follows that the initial concentration times the initial volume will equal the final concentration times the final volume because the sum does not vary.
Using the formula as follows;
C₁V₁ = C₂V₂
Where;
C₁ = initial concentration of the stock solution
C₂ = final concentration of the stock solution
V₁ = initial volume of the stock solution
V₂ = final volume of the stock solution
According to the information given in this question,
V₁ = 25mL = 25/1000 = 0.025L
V₂ = 2L
C₁ =?
C₂ = 0.103M
Using the formula; C₁V₁ = C₂V₂
C₁ = C₂V₂/V₁
C₁ = (0.103 × 2) / 0.025
C₁ = 0.206 / 0.025
C₁ = 8.24 M
Therefore, the stock solution should have a molarity of 8.24M.
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