Answer:
8.0 moles Ag
Explanation:
To find the moles of silver (Ag), you need to multiply the moles of Zn and AgNO₃ by the mole-to-mole ratio. This ratio is made of the coefficients from the balanced chemical equation. It is important to arrange the ratio in a way that allows for the cancellation of units.
2 AgNO₃ + 1 Zn -----> 2 Ag + Zn(NO₃)₂
^ ^ ^
5.0 moles Zn 2 moles Ag
----------------------- x ---------------------- = 10. moles Ag
1 mole Zn
8.0 moles AgNO₃ 2 moles Ag
---------------------------- x ---------------------------- = 8.0 moles Ag
2 moles AgNO₃
We needed to convert both reactants into the product because we wre not given a limiting reagent. The limiting reagent is the reactant that is completely reacted first. The limiting reagent in this reaction is AgNO₃ because it produces the smallest amount of product. As such, the actual amount of moles Ag is 8.0 moles.
