[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]
[tex]\longrightarrow \sf{Mg+2HCI \Longrightarrow MgCl_2+H_2}[/tex]
[tex]\longrightarrow \sf{molMg=129gMg \times \dfrac{1molMg}{24.305gMg=} }[/tex]
[tex]\small \sf{\longrightarrow molH_2=7.90molMg \times \dfrac{1molH_2}{1molMg}= 7.90molH_2 }[/tex]
[tex]\small \sf{\longrightarrow massH_2=7.90H_2 \times \dfrac{2.016g}{1molH_2}= 7.90molH_2= 15.9 \: gH_2}[/tex]
[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]
[tex] \small\bm{ The \: mass \: of \:H_2 \: produce \: will \: be \: 15.9 }[/tex] [tex]\bm{grams.}[/tex]
