6.665 grams of the 13 grams remain after 8 hours.
How much of a 13 gram sample of iron-52 would remain after 8 hours?
The decay equation for the 13 grams of iron-52 is:
[tex]N(t) = 13g*e^{(-ln(2)/8.3h)*t}}[/tex]
Where N is the amount of iron-52, and t is the time in years.
Where we used the fact that the half-life is exactly 8.3 hours.
Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:
[tex]N(8h) = 13g*e^{(-ln(2)/8.3h)*8h}} = 6.665g[/tex]
So 6.665 grams of the 13 grams remain after 8 hours.
If you want to learn more about half-life:
https://brainly.com/question/11152793
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