There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In [tex]Fe(NO_{3} )_{2}[/tex] , the valancy of Fe is +2 .
2 moles of [tex]e^{-}[/tex] are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of [tex]e^{-}[/tex] are required for the decomposition of 0.128 mole of Fe .
moles of [tex]e^{-}[/tex] are required = 0.256 moles
Charge on 1 mole of [tex]e^{-}[/tex] = 96500 C
Charge on 0.256 mole of [tex]e^{-}[/tex] = 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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