299.7 moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride.
Calculation,
The production of aluminium metal is given as,
[tex]Al^{+3} + 3e^{-}[/tex]→ [tex]Al[/tex]
The 3 moles of electrons require to produce 1 gm of atom of aluminium ( weight = 27 ) solution fluoride.
The number of moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride = 3mol×99.9g/1g
The number of moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride = 299.7 moles
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