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For which of the following reactions is S° > 0.

Choose all that apply.

2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g)


2CO2(g) + N2(g) ---->2CO(g) + 2NO(g)


2N2(g) + O2(g) -----> 2N2O(g)


S(s,rhombic) + 2CO(g) ----> SO2(g) + 2C(s,graphite)


NH4Cl(s) ----> NH3(g) + HCl(g)

Respuesta :

mickymike92

The entropy of the given reactions increases (S° > 0):

  • 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
  • NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.

What is entropy?

Entropy measure how disordered a system is. It a measure of how dispersed or random the total energy of a system is. The symbol for entropy is S.

A system in which entropy increases is one in which S° > 0.

The entropy of a system decreases when S° < 0.

Entropy of a system increases (S° > 0) if any change results in an increase in temperature, increase in number of molecules, or an increase in volume.

Considering the given systems, the entropy changes is as follows:

  • 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
  • 2CO2(g) + N2(g) ---->2CO(g) + 2NO(g) --> no change
  • 2N2(g) + O2(g) -----> 2N2O(g)  ---> decreases
  • S (s,rhombic) + 2CO(g) ----> SO2(g) + 2C (s,graphite) ---> no change
  • NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.

In conclusion, an increase in volume and moles of substances results in entropy increase.

Learn more about entropy at: https://brainly.com/question/26691503

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