A tire has a pressure of 1.8 atm at 20 degrees Celsius. At the end of a long trip, the tire pressure increased to 2.0 atm. What was the temperature of the air inside the tire (in degrees Celsius)?

Respuesta :

Answer:

52.57 Celsius

Explanation:

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Gay-Lussac's law

P1/T1 = P2/T2

pressure 1 / temperature1 = pressure2 / temperature2

temperature has to be in kelvin

20 degrees Celsius is 293.15

1.8 / 293.15 = 2.0 / temperature2

1.8 / 293.15 = 2.0 / x

293.15 * 2.0 = 586.3

586.3 divided by 1.8 =

325.722222222 kelvin which is

52.57222222200005 Celsius

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