A juggler is performing her act using several balls. she throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. this can be represented by the function h(t) = −16t2 15t 4. if the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor? 7.52 seconds 1.15 seconds 0.47 seconds 0.22 seconds

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Tutorconsortium364 Tutorconsortium364 · Answer 1 · 2022-08-15T11:34:19+02:00

The ball will take 1.15 seconds to hit the floor.

It is given that,

A juggler is performing her act using several balls. The height as a function of time is given by :

[tex]h(t) =-16t^{2} + vt +s[/tex].............(1)

where,

v is the speed of the ball

s is initial height

t is time taken

Putting h(t) = 0 and solving equation (1)

[tex]-16t^{2} + vt +s = 0[/tex]

[tex]-16t^{2} + 15t +4 = 0[/tex]

On solving above equation using graphing calculator and solving for t we get, t = 1.154 second.

Hence, the correct option is (b) " 1.15 seconds ".

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