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seat belt use in michigan in 2012 is estimated at 95%, which means 95% of people use their seat belts. suppose two independent drivers have been randomly selected.

Respuesta :

The probabilities are P1= 0.9025 , p2= 0.0475  ,P3= 0.0025

the probability that two of them uses seat belt is

P1 (seat belt, seat belt)= (95/100)*(95/100)

                                  = 361/400

                                  =0.9025

the probability that uses seat belt is 95% so the probability that does not uses seat  belt is 100% - 95%= 5%

now the probability that one use seat belt is

     P2( seat belt ,without seat belt)= (95/100)*(5/100)

                                                      =475/10000

                                                      =0.0475

now the probability that are not using seat belt

P3(without seat belt ,without seat belt)= (5/100)*(5/100)

                                                                =25/10000

                                                                =0.0025

Hence ,the probabilities are P1= 0.9025 , p2= 0.0475  ,P3= 0.0025

learn more about of probability here

https://brainly.com/question/15741126

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