The correct answer is Nitrogen.
From the given question the electronic configuration of the element is given as:
1s²2s²2p³
hence, we know that the maximum no of electrons in the sub-shell
s= 2
p=6
while in this p has only 6 electrons.
Thus by counting the number of electrons in each sub-shell we can know the atomic number as several electrons in an atom is equal to the atomic number of the atom.
thus, the no of electrons present is- 2+2+3= 7
For, 7 electrons the element present will be nitrogen with atomic number 7.
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