The dimensions of the cropped photo will be 9 inches by 9 inches
Step-by-step explanation:
Step 1 of 3
From the formula of area of square
Length x width = area
[tex]x^{2}[/tex] = area
But we are given the equation as
[tex](x+2)^{2}[/tex] = 121
Step 2 of 3
The equation gives the measures of the cropped dimension as "x". This means we need to solve the equation
[tex](x+2)^{2}[/tex] = 121
[tex]x^{2}[/tex] + [tex]2^{2}[/tex] + 2(x) (2) = 121
[tex]x^{2}[/tex] + 4 + 4x = 121
[tex]x^{2}[/tex] + 4x -117 = 0
[tex]x^{2}[/tex] + 13x - 9x -171 = 0
x( x+13) -9 (x+13) = 0
(x+13)(x-19) =0
This means
x = 9, -13
Step 3 of 3
Since, dimension can't be negative. So, the measure of dimension would be 9 inches by 9 inches
You can learn more about dimensions of square from
https://brainly.in/question/51828
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The question is incomplete. Therefore, complete question is
Liliana decides to crop a square photo 2 inches on each side to fit it into a frame. The area of the original photo was 121 square inches. In the equation [tex](x+2)^{2}[/tex] = 121, x represents the side measure of the cropped photo. What are the dimensions of the cropped photo
8 inches by 8 inches
9 inches by 9 inches
12 inches by 12 inches
13 inches by 13 inches
