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1. A market research survey in which 60 consumers were contacted states that 65% of all consumers of a certain product were motivated by the product's advertising. Find the confidence limits for the proportion of consumers motivated by advertising in the population, given a confidence level equal to 0.95.​

Respuesta :

The confidence limits for the proportion of consumers motivated by advertising in the population, given a confidence level equal to 0.95. is; CI = (0.47, 0.77)

How to find confidence Interval of Proportions?

We are given;

Sample Size; n = 60

sample proportion; p' = 65% = 0.65

Confidence level = 0.95

Now, formula for confidence interval of proportion is;

CI = p' ± z√(p(1 - p)/n)

At CL of 95%, z = 1.96Thus;

CI = 0.65 ± 1.96√(0.65(1 - 0.65)/60)

CI = 0.65 ± 1.96√0.00379167

CI = 0.65 ± 0.12

CI = (0.65 - 0.12), (0.65 + 0.12)

CI = (0.47, 0.77)

Read more about confidence Interval of Proportions at; https://brainly.com/question/15712887

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