A model rocket is launched with an initial upward velocity of 156ft/s . The rocket's height h (in feet) after seconds is given by the following. h= 156t-16t^2

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MrRoyal MrRoyal · Answer 1 · 2022-09-07T19:09:03+02:00

The values of t for which the rocket's height is 60 feet are t = 0.40 and t = 9.35

The function is given as:

h = 156t - 16t^2

When the height is 60 feet, we have:

156t - 16t^2 = 60

Rewrite as:

16t^2 - 156t + 60 = 0

Divide through the equation by 4

4t^2 - 39t + 15 = 0

Next, we solve the equation using a graphing calculator

From the graphing calculator, we have:

t = 0.40 and t = 9.35

Hence, the values of t for which the rocket's height is 60 feet are t = 0.40 and t = 9.35