Answer:
Step-by-step explanation:
Yochanan traveled a total of 35 km in 1.5 hours, part by walking 5 km/h, and part by riding a bus at 60 km/h. You want to know the distances covered in each mode of transportation.
The relation between time, speed, and distance is ...
distance = speed × time
Let t represent the time spent riding the bus. Then (1.5 -t) is the time spent walking. The total distance covered at the different speeds is the sum of products of speed and time:
5(1.5 -t) + 60(t) = 35
Simplifying the equation gives ...
7.5 +55t = 35
55t = 27.5 . . . . . . . subtract 7.5
t = 1/2 . . . . . . . . . divide by 55
1.5-t = 1.5 -0.5 = 1 . . . . . time spent walking
The distance traveled by walking is ...
(1 h)(5 km/h) = 5 km . . . . walking distance
The distance traveled by bus is ...
(0.5 h)(60 km/h) = 30 km . . . . bus distance
Yochanan covered a distance of 35 km in 1.5 hours, some of it on foot at a speed of 5 km/h and some of it on a bus moving at 60 km/h.
In mathematics, it deals with numbers of operations according to the statements.
Here,
Let the time taken by the Yochanan to go through the bus be t.
time is taken to the bus stop through walk = 1.5 - t
Now,
According to the question,
5(1.5 - t) + 60t = 35
7.5 - 5t + 60t = 35
t = 0.5
Now,
Distance traveled by walk = 5(1.5 - 0.5) = 5 Km
Distance traveled by bus = 35 - 5 = 30 Km
Thus, Yochanan covered a distance of 35 km in 1.5 hours, some of it on foot at a speed of 5 km/h and some of it on a bus moving at 60 km/h.
Learn more about arithmetic here:
brainly.com/question/14753192E
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