The expression given is
[tex]2x^3+5x^2+6x+15[/tex]
Arranging the expression into two groups
[tex](2x^3+5x^2)+(6x+15)[/tex][tex]\begin{gathered} \text{Factor out x}^2\text{ from }2x^3+5x^2 \\ =x^2(2x_{}+5) \end{gathered}[/tex]
Factor out 3 from 6x + 15
[tex]=3(2x+5)[/tex]
Then the expression is now resulted into
[tex]=x^2\mleft(2x+5\mright)+3\mleft(2x+5\mright)[/tex][tex]\begin{gathered} \mathrm{Factor\: out\: common\: term\: }2x+5 \\ =\mleft(2x+5\mright)\mleft(x^2+3\mright) \end{gathered}[/tex]
Hence, the factors of the expression are
[tex]\mleft(2x+5\mright)\mleft(x^2+3\mright)[/tex]
