consider the functions f(x)=x+9 and g(x)= √-x-1. Determine each of the following.(f°g)(x)=Give the domain of (f°g)(x).(g°f)(x)=Give the domain of (g°f)(x).

The domain of this function is when the term under the root is positive or 0 because there is no root for a negative number in the real numbers, this only happens when:

[tex]-x-1\ge0\Rightarrow-x\ge1\Rightarrow x\leq-1[/tex]

Then, the domain is when x is:

[tex]x=(-\infty,-1\rbrack[/tex]

Then, for the second part:

[tex](g\circ f)(x)=\sqrt[]{-(x+9)-1}=\sqrt[]{-x-10}[/tex]

The domain for this function is only when the term under the root is positive or 0, so:

[tex]-x-10\ge0\Rightarrow-x\ge10\Rightarrow x\leq-10[/tex]

Then, the domain is:

[tex]x=(-\infty,-10\rbrack[/tex]

consider the functions f(x)=x+9 and g(x)= √-x-1. Determine each of the following.(f°g)(x)=Give the domain of (f°g)(x).____(g°f)(x)=Give the domain of (g°f)(x).____

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consider the functions f(x)=x+9 and g(x)= √-x-1. Determine each of the following.(f°g)(x)=Give the domain of (f°g)(x).(g°f)(x)=Give the domain of (g°f)(x).