Answer:
stress = 16.9 MPa
Explanation:
The stress in the cable can be calculated as:
[tex]\text{Stress = }\frac{F}{A}[/tex]Where F is the force and A is the area. So, the area can be calculated as:
[tex]A=\pi^{}\cdot r^2[/tex]Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:
[tex]\begin{gathered} A=3.14(4\operatorname{mm})^2 \\ A=50.24\operatorname{mm}^2 \end{gathered}[/tex]Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:
[tex]\text{stress = }\frac{850N}{50.24mm^2}=16.9\text{MPa}[/tex]Therefore, the answer is 16.9 MPa
