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Pedro, a restaurant waiter, has twice as many tips as his partner Alfredo. If Pedro gives Alfredo $34, Pedro would have 5/11 of what Alfredo has. How much do they have

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SOLUTION

Given the information on the question tab;

[tex]Let\text{ Pedro's tips be p, and that of Alfredo be a.}[/tex][tex]\begin{gathered} From\text{ the statement;} \\ p=2a-----(1) \\ p-34=\frac{5}{11}(a+34)----(2) \end{gathered}[/tex][tex]\begin{gathered} Plug\text{ p=2a into equation \lparen2\rparen;} \\ 2a-34=\frac{5}{11}(a+34) \\ 22a-374=5a+170 \\ 22a-5a=170+374 \\ 17a=544 \\ a=\frac{544}{17} \\ a=\text{ \$}32 \\ \therefore p=2(32) \\ p=\text{ \$}64 \\ a+p=64+32=\text{ \$}96 \end{gathered}[/tex]

Final answer:

[tex]\begin{gathered} Alfredo\text{ has \$32.} \\ Both\text{ of them have \$96} \end{gathered}[/tex]

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