Given:
Machine A covers 5/8 square feet in 1/2 hour.
Machine B covers 2/3 square feet in 1/3 hour.
Solution:
The unit rate of the machine A will be as
[tex]\begin{gathered} \text{Unit Rate=}\frac{\frac{5}{8}}{\frac{1}{2}} \\ =\frac{5}{8}\ast\frac{2}{1} \\ =\frac{10}{8} \\ =1.25 \end{gathered}[/tex]The unit rate of the machine B will be as
[tex]\begin{gathered} \text{Unit Rate=}\frac{\frac{2}{3}}{\frac{1}{3}} \\ =\frac{2}{3}\ast\frac{3}{1} \\ =2 \end{gathered}[/tex]Answer:
Hence, the unit rate of the machine B is greater.
